Синтез логических схем на логических элементах малой степени интеграции (стр. 4 из 5)
y2(x Q1 Q2 Q3) = v(10, 11, 12, 13)
y3(x Q1 Q2 Q3) = v(3, 9, 12, 13)
y4(x Q1 Q2 Q3) = v(3, 8, 10, 13, 14)
Запрещенные наборы – 1, 2, 4, 5, 7,15
q1
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | α | α | ||
| 01 | + | + | + | 1 |
| 11 | 1 | 1 | + | 1 |
| 10 | α |
q2
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | α | β | 1 | |
| 01 | + | + | + | 1 |
| 11 | + | 1 | ||
| 10 | α | β | 1 |
q3
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | 1 | β | ||
| 01 | + | + | + | |
| 11 | 1 | + | ||
| 10 | α | β | 1 |
y1 =
y2 =
y3 =
y4 =
Минимизация с помощью карт Карно
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | + | + | ||
| 01 | + | + | + | 1 |
| 11 | + | 1 | ||
| 10 |
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | + | + | ||
| 01 | + | + | + | |
| 11 | 1 | 1 | + | |
| 10 | 1 | 1 |
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | + | 1 | + | |
| 01 | + | + | + | |
| 11 | 1 | 1 | + | |
| 10 | 1 |
y1 =
y2 = 
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | + | 1 | + | |
| 01 | + | + | + | |
| 11 | 1 | + | 1 | |
| 10 | 1 | 1 |
y3 =
y4 = 
Выбор типа триггера
Синтез на D - триггере
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | 1 | 1 | ||
| 01 | + | + | + | 1 |
| 11 | 1 | 1 | + | 1 |
| 10 | 1 |
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | 1 | 1 | ||
| 01 | + | + | + | 1 |
| 11 | + | 1 | ||
| 10 | 1 | 1 |
D1 =
D2 = 
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | 1 | |||
| 01 | + | + | + | |
| 11 | 1 | + | ||
| 10 | 1 | 1 |
D3 =
Синтез на JK – триггере
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | 1 | 1 | ||
| 01 | + | + | + | х |
| 11 | х | х | + | х |
| 10 | 1 |
| Q2Q3 x Q1 | 00 | 01 | 11 | 10 |
| 00 | х | х | х | х |
| 01 | + | + | + | |
| 11 | + | |||
| 10 | х | х | х | х |
J1 =
K1 = 